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Formulate a conversion of 4-octyne to 4,5-dichlorooctane as shown in the equation below. You may use any inorganic reagent.
4 octyne => 4,5 dichlorooctane
The amount (N = grams) of radioactive material present in a sample as a function of time is given by the following equation, where No is the amount present at t = 0. : N (t) = No e^-kt At Great Basin College, we have a specimen of a highly radioac..
A bunsen burner uses the combustion of butane (c_4_H_10_) as a means to provide heat. If during a laboratory experiment the class uses 875 grams of butane. how many grams of each product will be produced?
the freezing point of a CaCl2 solution is -25 degrees C. a) what is the molality(m) of the CaCl2 solution? b) what is the boiling point of the CaCl2 solution
Calculate the masses of the reactants and products of the following equation. Please show work.
Liquid benzene, C6H6, (density = 0.877 g/mL) can be used as a fuel. What is ?H in kJ for the combustion of 2.86 L of benzene producing CO2(g) and H2O. Assume that the heat of combustion of benzene is -4.18 x 103 kJ/mol.
given that hclo4 an aqueous solution is 4.810-8 m write the equation for the reaction of hclo4 compute h3o oh- poh and
Which entries below should have the highest standard molar entropy? Place them in order of increasing standard molar entropy. ex: a>b>c>d.
A particular voltaic cell operates on the reaction below, giving an emf of 0.865 V. Calculate the maximum electrical work generated when 20.0 g of zinc metal is consumed. Zn(s) + CI2(g) ? Zn2+(aq) + 2 Cl ?(aq)
Pretend you run a reaction and your theoretical yield is 5.25 grams, but you isolate 5.50 grams. What is the most likely reason for the excess weight
A total of 0.160 g of this subunit was dissolved in enough water to produce 2.00 mL of solution. At 28 C the osmotic pressure produced by the solution was 0.138atm. What is the molar mass of the protein?
when 15.0g of steam drops in temperture from 275.0C to 250.0C how much heat is released csteam=2.01j/gC
The pH after adding 5.0mL, 10.0mL, 15.0mL, 20.0mL (keeps increasing by 5)... 50mL of KOH aqueous solution to the 50.0 mL sample of the HF solution.
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