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Calculate the standard free energy change, and determine whether or not the following reaction is spontaneous under standard conditions:
H2O2(l) --> H2O(l) + ½O2(g)
Use the following values for ?Gf°: H2O2(l) = -120.4 kJ/mol; H2O(l) = -237.2 kJ/mol.
A. -457.6 kJ; spontaneousB. 475.6 kJ; not spontaneousC. -116.8 kJ; spontaneousD. 116.8 kJ; not spontaneousE. -287.2 kJ; spontaneous
Because the turnover number for both substrates is nearly identical, what factors might be involved that explain the different ratio for the two substrates?
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