Evaluate the quantity of sodium fluoride in kilograms

Reference no: EM13550119

Fluoridation is the process of adding fluorine compounds to drinking water to help fight tooth decay. A concentration of 1 ppm of fluorine is sufficient for the purpose (1 ppm means one part per million, or 1 g of fluorine per 1 million g of water). The compound normally chosen for fluoridation is sodium fluoride, which is also added to some toothpastes.

Calculate the quantity of sodium fluoride in kilograms needed per year for a city of 50,000 people if the daily consumption of water per person is 115.0 gallons. (Sodium fluoride is 45 percent fluorine by mass. 1 gallon = 3.79 L; 1 ton=2000lb; 1 lb= 453.6 g; density of water =1.0 g/mL

Reference no: EM13550119

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