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Calculate the boiling point of a solution prepared by dissolving 70.0 g of naphthalene, C10H8 (a nonvolatile nonelectrolyte), in 220.0 g of benzene, C6H6. The Kb for benzene = 2.53°C/m. The boiling point of pure benzene is 80.1°C.
87.8°C
73.8°C
83.2°C
86.4°C
106.3°C
oxygen is burned completely, 3.86 grams of CO2 and 1.26 grams of H2O are produced. What is the empirical formula of the compound?
What is the simplest formula for Chalcocite if a sample of this ore contains 8.274 g copper and 2.088 g sulfur?
A compound that contains only C and H was burned in excess O2 to give CO2 and H2O. When 0.270 g of the compound was burned, the amount of CO2 formed reacted completely with 20.0 mL of 2.00 M NaOH solution according to the equation:
How many grams of oxygen gas are required to produce 7.68 kJ of heat when hydrogen gas burns at constant pressure to produce gaseous water?
An automobile gasoline tank hold 21kg of gas. When the gasoline burns, 84kg of oxygen is consumed and carbon dioxide and water vapor are produced. What is the total combined mass of carbon dioxide and water that is produced?
Calculate the pH of a solution prepared by dissolving 0.15 of sodium benzoate and 0.3 of benzoic acid in water sufficient to yield 1L of solution.
Assuming that the 3s- and 3p-orbitals will form molecular orbitals similar to those formed when 2s- and 2p-orbitals interact, according to molecular orbital theory
napthalene lowered the freezing point of the solvent by 0.780K. Calculate the molar mass of the compound. [Kf of napthalene= 6.94 K*kg/mol]
Naphthalene is the simplest of the polycyclic aromatic hydrocarbons and can be represented by three resonance structures
how much dry solute would you take to prepare each of the following soluions from the dry solute and the solvent? Part A. 124ml of 0.555M KCl. Part B 10g of .530m KCl. Part C 107g of 5.4% KCl solution by mass.
How many grams of hydrogen would have to react to produce 71.9 kJ of energy from the reaction 2H2 + O2 --------> 2H2O + 484kJ?
what should the stock concentration of atp be so that if you pipette a 100 uL aliquot you will obtain a final concentration of 2mM in an assay volume of 3.0 mL
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