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The equilibrium constant for the following reaction is 6.59×10-2 at 927 °C.
2 SO3(g) <-----> 2 SO2(g) + O2(g) K = 6.59×10-2 at 927 °C
Calculate the equilibrium constant for the following reactions at 927 °C
(a) 2 SO2(g) + O2(g) <----> 2 SO3(g) K = ________
(b) SO3(g) <-------> SO2(g) + 1/2 O2(g) K = _________
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