During busy periods a new customer walks into lhs

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Reference no: EM1381936

Steves Barber Shops

Steve needs to decide where to get a haircut. He has narrowed the choice down to two local hair salons - Large Hair Salon (LHS) and Small Hair Cutters (SHC).

During busy periods, a new customer walks into LHS every 15 minutes (with a standard deviation of 15 minutes). At SHC, a customer walks in every hour (with a standard deviation of 1 hour). LHS has a staff of 4 barbers, while SHC has 1 barber. A typical service time at either salon lasts 30 minutes (with a standard deviation of 30 minutes).

Q1. If Newt walks into LHS during a busy period, how long (in minutes) must he wait in line before he can see a barber? (Only include the waiting time, not any service time)

Q2. How many customers, on average will be in LHS, including both waiting in line and being served?

Q3. If Newt goes to SHC, how long (in minutes) must he wait in line before his haircut starts?

Q4. Assume that it takes Newt 10 minutes to leave work and walk to LHS and 10 minutes to walk back (i.e. each way of the walk takes 10 minutes). How long (in minutes) will he need to leave work for to get a haircut at LHS?

Q5. LHS will buy out SHC. LHS will then close SHC's operations and serve all customers, including existing SHC customers, at the LHS location only. Assuming that the previous traffic of SHC customers now flows to the LHS location, what is the new inter-arrival time (in minutes) at LHS?

Mark Stamp

Q6. Mark approves study abroad documents for Penn. Students must wait in line with their forms outside Mark office. One student at a time is allowed in his office and Mark takes precisely 25 minutes to evaluate each student's set of documents. On average 2.2 students per hour go to his office and they spend on average 160 minutes trying to get their forms approved (time waiting in queue plus time in Mark office having him evaluate their documents). On average, how many students are waiting outside of Mark office? Ignore start-of-the-day and end-of-the-day effects. (Hint: You do not need to know CVa and CVp to solve this question but if you want, you can assume that CVa=1 and the standard deviation of the processing time is zero.)

Reference no: EM1381936

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