Distribution of raw scores with a mean

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Given a normal distribution of raw scores with a mean of 60 and a standard deviation of 8, what proportion of cases fall:

a) between a raw score of 50 and 80?

50-60/8= -1.25 = .3944

80-60/8= 2.5 =   .4938

88.82% of scores fall between

b) between a raw score of 48 and 57?

48-60/8 = -1.5 =   .4332

57-60/8 = -.375 =  .4999

93.31% of scores fall between a raw scorAn

Reference no: EM132024924

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