Determining the unsymmetrical fault

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Reference no: EM131838406

The "system" shown is composed of a 50Hz, 50 MVA, 13.2kV star-grounded alternator which is connected to a line through a delta/wye transformer. The positive, negative and zero sequence impedances of the alternator are j0.1, j0.1 and j0.5 p.u. respectively. The transformer rated at 13.2kV delta/120kV wye, 50 MVA with star solidly grounded has the sequence impedances of X"=X2=X0=j0.1 p.u. each. For the unsymmetrical fault shown determine:

a. The fault current, IF, at the fault point (both p.u. and actual values)

b. The line currents Ia , Ib and Ic (both p.u. and actual values)

c. The line voltages Vag , Vbg and Vcg (both p.u. and actual values)

1636_unsymmetrical fault.png

Reference no: EM131838406

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