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Q1) Suppose you require building confidence interval for population mean within some given situation. Naturally, you should find out whether you must use either t-distribution or z-distribution or possibly even neither based upon information known/gathered in the situation. Therefore, based upon given information for each situation below, find out which (t-, z- or neither) distribution is suitable Then if you can utilize either a t- or z- distribution, provide associated critical value (critical t- or z- score) from that distribution to reach given confidence level.
a) 95% confidence n=52 sigma unknown population data believed to be normally distributed.
b) 90% confidence n=7 sigma unknown population data believed to be very skewed.
c) 95% confidence n=85 sigma unknown population data believed to be skewed right.
d) 99% confidence n=15 sigma unknown population data believed to be normally distributed.
The remaining 5 were not given the overview. Here are the scores for students in each group:
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The p-value of the test is closest to:
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If 25 men aged 18-24 are arbitrarily chosen, determine probability that their mean serum cholesterol level is between 165 and 200.
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