Determine z statistic and p-value

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Of the 400 respondents in the Christmas tree market survey, 43% had no children at home and 57% had at least one child at home. Corresponding figures for most recent census are 48% with no children and 52% with at least one child. Test null hypothesis that telephone survey technique has the probability of selecting the household with no children which is equal to value obtained by census. Give z statistic (rounded to two decimal places) and P-value. What do you conclude? (Use = 0.10.).

Reference no: EM13108958

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