Determine the limiting reactant when 1140g of fe2o3 molar

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If Fe2O3(s) + 3CO (g)--> 2Fe (s) + 3 CO2(g)
1. The empirical formula of butene is CH2. Based on a molar mass is 56.1 g.mol, determine the molecular formula of the compound?

2. How many grams of Fe (molar mass = 55.85 g/mol) can be formed from 96 g of Fe2O3 (molar mass =159.69 g/mol) and excess CO?

3. Determine the limiting reactant when 114.0g of Fe2O3 (molar mass = 159.69 g/mol) are reacted with 56.8 g of CO (molar mass = 28.01 g/mol)?

Reference no: EM13645025

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