Determine the fraction of heat lost from the glass

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Reference no: EM131277072

Consider a flat-plate solar collector placed on the roof of a house. The temperatures at the inner and outer surfaces of the glass cover are measured to be 28°C and 25°C, respectively. The glass cover has a surface area of 2.5 m², a thickness of 0.6 cm, and a thermal conductivity of 0.7 W/m · °C. Heat is lost from the outer surface of the cover by convection and radiation with a convection heat transfer coefficient of 10 W/m²· °C and an ambient temperature of 15°C. Determine the fraction of heat lost from the glass cover by radiation.

Reference no: EM131277072

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