Determine the energy of the lower stationary state

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Reference no: EM13510771

A line in the x-ray spectrum of gold has a wavelength of 18.5 pm(=18.5x10^12 m) The emitted x-ray photons corresponds to a transition of the gold atom between two stationary states, the upper one of which has the energy -13.7 keV. What is the energy of the lower stationary state?

Reference no: EM13510771

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