Determine the energy of the first photon emitted

Reference no: EM13268075

You are shining ultraviolet light on a gas of an unknown element. You know that an electron starts in a ground state with an energy of -17.30 eV. The electron absorbs a 4.00-eV photon. The electron immediately drops to an intermediate energy state Einter of energy -16.50 eV (in this case we will assume it emits a photon when it drops to the intermediate state, though most often the energy is lost through other means). After several seconds the electron drops back down to the ground state.

1. What is the energy of the state which the electron is in after absorbing the UV photon?

2. What is the energy of the first photon emitted?

3. What is the energy of the second photon emitted and is this process considered fluorescence or phosphorescence? (Both answers must be correct for the answer to be correct.)

Reference no: EM13268075

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