Determine the delta h for the neutralization reaction

Reference no: EM13490718

1) How do I find the delta H for the neutralization reaction given: HCl+NaOH-->H2O+NaCl using 0.05L of .5M HCl 0.055L of .5M NaOH Delta T=3.4Kelvin moles of H2O formed=.025moles of H2O I tried: (.105L)(4.18)(3.4)=1.49226 2) .105L of .25 NaCl solution is formed in the reaction. Its density is 1.01 g/cm^3 and its specific heat capacity, Cs, is 3.80 J/(K*g). How do I calculate its heat capacity both for C(rxn) and C(calorimeter)?

Reference no: EM13490718

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