Reference no: EM132330220

Question

Consider the program below. The program determines the admission fee of the ageGroup that user inputs. You can use the if-else statements to match the ageGroup and the fee. But you can also use a dictionary instead of the if-else to accomplish the same task with only one line of code.

def main():

## Determine an admission fee based on age group.

print("Enter the person's age group ", end="")

ageGroup = input("(child, minor, adult, or senior): ")

print("The admission fee is", determineAdmissionFee(ageGroup), "dollars." )

##def determineAdmissionFee(ageGroup):

## if ageGroup == "child": # age < 6

## return 0 # free

## elif ageGroup == "minor": # age 6 to 17

## return 5 # $5

## elif ageGroup == "adult": # age 18 to 64

## return 10

## elif ageGroup == "senior": # age >= 65

## return 8

def determineAdmissionFee(ageGroup):

dict = {"child":0, "minor":5, "adult":10, "senior":8}

return dict[ageGroup]

main()

a. Rewrite the code using a dict instead of if-else, write the main to ask user to input what year and then print the corresponding rank name eg 1 = Freshman.

def determineRank(years):

if years == 1:

return "Freshman"

elif years == 2:

return "Sophomore"

elif years== 3:

return "Junior"

else:

return "Senior"