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The speed of a bullet as it travels down the barrel of a rifle toward the opening is given by y = (-4.60 x 107) t2 + (3.00 x 105) t, where v is in meters per second and t is in seconds. The acceleration of the bullet just as it leaves the barrel is zero.
(a) Determine the acceleration and position of the bullet as a function of time when the bullet is in the barrel. (Use t as necessary and round all numerical coefficients to exactly 3 significant figures.)
(b) Determine the length of time the bullet is accelerated.
(c) Find the speed at which the bullet leaves the barrel.
(d) What is the length of the barrel?
A 4.3 gram bullet leaves the muzzle of a rifle with a speed of 336 m/s. Determine what force is exerted on the bullet while it is traveling down the 0.85 meter long barrel of the rifle
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