Determine expected frequencies of individual progeny

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Reference no: EM1397091

1. Sepia& Ebony have a published distance of 44.7 M.U. For that data, run a Chi-square test to see if the data obtained fits with that distance. The following questions will walk you through that process

a. First, determine expected frequencies of each individual progeny possibility based on the 44.7 M.U. distance. Do this by showing a punnet square for frequencies. Think about what M.U.s mean and how that affects gamete probabilities. Assume that crossing over occurs equally between males and females.

b. From your punnet square, calculate the expected frequencies of each phenotype based on a 44.7 M.U. distance.

c. Determine the expected number of flies of each category (round to the nearest hundredth of a fly).

	WT	Ebony (body)	Sepia (eye)	Sepia&Ebony	Total (contributing)
Observed	2313	317	274	454	3358
Expected

	Female and male combined
sepia (se) & ebony(e)	wild type	just dark bodies	just darker eyes	darker eyes and bodies	Total
	2313	317	274	454	3358

Reference no: EM1397091

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