Determine confidence interval of population mean

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Irate patient complained that cost of doctor's visit was too high. She arbitarily surveyed 20 other patients and found that mean amount of money they spent on each doctor's visit was $44.80. Standard deviation of sample was $3.53. Determine point estimate of population mean. Determine the 95% confidence interval of population mean. Suppose the variable is normally distributed.

Reference no: EM13110561

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