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Derive an expression and numerical value for the distance

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Question: Derive an expression and numerical value for the distance of closest approach of an alpha to a gold nucleus, when the impact parameter is b=0 (i.e., a head-on collision). Use conservation of energy, and take the alpha particle energy to be 6 MeV (1 MeV = 1.602E-13 J). How does this compare with the Bohr radius? Why the difference, if any?

Reference no: EM132192957

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