Derivatives of tan theta

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An observer to a rocket launch was 1800 feet from takeoff position. The observer found the angle of elevation of the rocket as a function of time to be theta=3t/(2t+5). Therefore, the height h (in feet) of the rocket was h = 1800 tan (3t/(2t+5)). Find the time rate of change of height after 4.0 seconds.

Reference no: EM13127792

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