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Draw a chair conformation of cyclohexane with one CH3CH2 group and one CH3 group that fits in the description: A cis-disubstituted cyclohexane with an axial CH3 group
Calculate the amount of C6H12O6 (glucose) you would need to measure out on a balance in order to have 1.504 x 10^23 molecules of C6H12O6 (glucose)
A copper, Cu(s), electrode is immersed in a solution that is 1.00 M in ammonia, NH3, and 1.00 M in tetraamminecopper(II), [Cu(NH_3)_4]^{2+}. If a standard hydrogen electrode is used as the cathode, the cell potential, E_cell, is found to be 0.076 ..
Compute the number of electrons in a flake of pure gold valued at $0.44. Assume that the price of gold is $1630.0/troy oz. (1 troy oz = 31.1 g)
Finding Number of Atoms in a Molecule from Molecular Weight, As determined from the gas law, the molecular weight of a substance is eight times the atomic weight
calculate the number of moles of KOH in 5.5mL of a .36 M KOH solution. what is the pOH of the solution?
A mixture of 8.0mol of H2 (g) and 4.0mol of O2 (g) is placed in a sealed evacuated container made of a perfect insulating material at 28 degrees C. The mixture is ignited with a spark and it reacts to form liquid water. Find the temperature of the..
In order to produce 10000.0 kJ of energy, how many grams of oxygen must react?
calculate the moles of h2 present in this gas sample. . 9. 1.0 gram of water at 25 c is heated to 100 c at which point
calculating theoretical yield for this experiment. It is a dehydration synthesis where one mol of hydrated salt yields 3 mol hydrates and 1 mol of anhydrous salt.
A pound of coffee beans yields 30 cups of coffee (4 cups = 1 q). How many milliliters of coffee can be obtained from 1 g of coffee beans.
theres just no way they could deal with that. he went on obviously if you get drought indices like these theres no
A compound is known to have a free amino group with a pKa of 8.8, and one other ionizable group with a pKa between 5 and 7. To 100 mL of a 0.2 M solution of this compound at pH 8.2 was added 40 mL of a solution of 0.2 M hydrochloric acid.
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