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Problem- 0.00 mL of 1.000M HA (a weak acid) was mixed with a 5.00mL NaOH. Then the mixture was diluted to 50.0mL with water. The pH of the solution reads 5.00.
1. What is the chemical equation between HA and NaOH?
2. Calculate moles of each. What is the limiting reactant?
3. Calculate the moles of each left at the end of this reaction. Calculate the Molatirites for each. (What is the total volume?)
4. Write a balanced equation for dissociation of HA (aq) in water.
5. Write an expression for K for the equation above.
6. Draw the appropriate ICE table. Fill in all the information.
7. Calculate K.
8. What is the difference between K and Ka? IS the K from question above Ka? Explain.
Explain the each and every step in detail for help
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