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1. I suspect that around 75% of my students will come to class each day (except for the exam dates.). How large sample do I need to ensure a 94% confidence with a margin of error of no more than 3%.
2. Amy is interesting in knowing whether there's a difference in how much the boys and girls spend on lunches at her school. She collected a sample of 28 boys from her school and they spent an average of $7.52 with standard deviation of $4.89. She also collected a sample of 15 girls from her school and they spent an average of $9.87 with standard deviation of $1.24. Construct a 95% confidence interval for the difference in the average spending for lunches of the boys and the average spending for lunches of the girls? Is your answer reliable? Why or why not?
1 the number of customers at quiet morning bakery is believed to follow a poisson distribution with a mean of 2
As a condition of employment, Fashion Industries applicants must pass a drug test. Of the last 220 applicants 14 failed the test. Develop a 99 percent confidence interval for the proportion of applicants that fail the test. Would it be reasonable ..
a doctors office staff studied the waiting times for patients who arrive at the office with a request for emergency
What is the probability that the percentage in the sample will deviate from the population percentage by no more than 7 percentage points?
A coin is flipped e times and heads (h) or tails (t) are recorded:
you select 3 bottles at random from a large production batch of bottled water. you guess that 80 of the bottles in the
recall the gas station example where y is the daily revenues from the gas station. suppose a random sample of 5 days
find the sample size needed to estimate the percentage of adults who have consulted fortune tellers. use a 0.03 margin
in a study of the effectiveness of garlic for lowering cholesterol 17 subjects were treated with garlicin which is
Indicate with Yes or No whether the given statement could apply to a data set consisting of 1,000 values that are all different. a. The 29th percentile is greater than the 30th percentile.
Standard deviation of 12%. Assume that scores in both classes follow a normal distribution. Convert Maria's midterm score of 84 to a standard z score.
in a study of 23 criminals convicted of antitrust offenses the average age was 55 years with a standard deviation of
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