Confidence interval for true proportion of all households

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Retailers report that the use of cents-off coupons is increasing - the proportion of all households that use coupons comes to .64. Suppose that this estimate was based on a random sample of 600 households (i.e., n = 600 and p = .64). Construct a 95% confidence interval for π, the true proportion of all households that use coupons.

Reference no: EM13156604

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