Confidence interval for the proportion of kansas residents

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In late June 2012, Survey USA published results of a survey stating that 56% of the 600 randomly sampled

Kansas residents planned to set off fireworks on July 4th.

(a) Find a 90% confidence interval for the proportion of Kansas residents planned to set off fireworks on July 4th.

I need help with the ones below that go with (a)

  1. TRUE or FALSE: In part (a), if a 95% confidence interval is constructed, the interval would be wider.
  2. TRUE or FALSE: If another 600 Kansas residents were sampled at random (in late June 2012), the sample proportion that planned to set off fireworks on July 4th would fall in the interval constructed in part (a) with 90% probability.

Reference no: EM132479281

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