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Confidence interval for the proportion of accidents

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Reference no: EM131244062

Can anyone do this question in 10 mins please.

An occupational health and safety survey of 123 industrial accent claims have revealed that 71 were due to untidy working conditions and thus preventable.

Part A) Calculate a 90% confidence interval for the proportion of accidents that are due to untidy working conditions.

Answer: We are 90% confident that the true population proportion of preventable accidents is between Answer and Answer.

Part B) What sample size is needed if the survey company from the previous question wants to be 90% confident of being correct to within + or - 0.07 of the population proportion of accidents that are due to untidy working conditions? Assume that no information is available from past data, thus the population proportion equals 0.50.

Answer: Answer

Part C) How would the sample size change if we were to assume our sample proportion discussed above is equal to the population proportion?

SmallerLargerSame SizeNot Enough Information

Reference no: EM131244062

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