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How much time do Americans spend eating or drinking? Suppose for a random sample of 1001 Americans age 15 or older, the mean amount of time spent eating or drinking per day is 1.22 hours with a standard deviation of .65 hour.
A) A histogram of time spent eating and drinking each day is skewed right. Use this result to explain why a large sample size is needed to construct a confidence interval for the mean time spent eating and drinking each day.
C) Determine and interpret a 95% confidence interval for the mean amount of time Americans age 15 or older spend eating and drinking each day.
D) Could the interval be used to estimate the mean amount of time a 9-year-old American spends eating and drinking each day? Explain.
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Assuming the sample size of 40 can be considered as large, compute the confidence interval for a confidence level of 90%.
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He surveys several businesses and finds the standard deviation in monthly advertising costs is $23 for 12 hair salons, and $43 for 8 nail salons.
The result for University X was a mean of 5 hours and an estimated population variance of 2 hours; for University Y; and for University Z. What should you conclude? Use the .05 level. What should you conclude? Use the .05 level.
A random sample of 72 statistics students was taken to estimate the proportion of students who are also in the Math Club. The 90% confidence interval was 0.438 to 0.642. Using this information, what sample size would be necessary to estimate the t..
At.01 significance level is it sensible to conclude that modification decreased the number of traffic accidents?
For each of the F statistics given above find the degrees of freedom and an approximate P-value. Summarize the results of these tests.
The state highway department is studying traffic patterns on one of the busiest highways in the state. As part of the study, the department needs to estimate the average number of vehicles that pass an intersection each day. A random sample of 64 ..
Suppose that sales of lemonade and sales of brownies are independent, determine standard deviation in his revenue.
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