Reference no: EM131042543

Can someone tell me if this is done correctly or if I did it wrong and if it is can you please show me the right way to solve this.

I ended up with 

x²>x²_{0.05 = 7.815}

df = 4-1 = 3

test statistics = 4.011

Since the calculated value of chi square is 4.011 is less than the crital value which is 7.815 we do not reject ho at 5% level of significance. So we conclude that men and women not select different breakfast.

Do men and women select different breakfasts? The breakfasts ordered by randomly selected men and women at a popular breakfast place is shown in Table 11.55. Conduct a test for homogeneity at a 5% level of significance. 

	French Toast	Pancakes	Waffles	Omelettes	Total
Men	47	35	28	53	163
Women	65	59	55	60	239
Total	112	94	83	113	402