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Chi-Square test for goodness of fit for Poisson distribution.
Banner Mattress and Furniture Company wishes to study the number of credit applications received per day for the last 300 days.
Number of Credit Applications
Frequency (Number of Days)
0
50
1
77
2
81
3
48
4
31
5 or more
13
To interpret, there were 50 days on that no credit applications were received, 77 days on which only one application was received, and so on. Would it be reasonable to conclude that the population distribution is Poisson with a mean of 2.0? Use the .05 significance level. Hint: To find the likely frequencies use the Poisson distribution with a mean of 2.0. Find the probability of exactly one success given a Poisson distribution with a mean of 2.0. Multiply this probability by 300 to find the expected frequency for the number of days in which there was exactly one application. Conclude the expected frequency for the other days in a similar manner.
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