Already have an account? Get multiple benefits of using own account!
Login in your account..!
Remember me
Don't have an account? Create your account in less than a minutes,
Forgot password? how can I recover my password now!
Enter right registered email to receive password!
To compute a 95% confidence interval for the population mean.
How healthy are the employees at Direct Marketing Industry? A random sample of 14 employees was taken, and the number of days each was absent for sickness was recorded during a 1-year period. The sample mean was 6.1 days with a standard deviation of 4.3 days.
Create a 95% confidence interval for the population mean days absent for sickness based on this sample. Select the answer closest to your results.
For each lettered part, a through c, examine the two given sets of numbers. Without doing any calculations, decide which set has the larger standard deviation and explain why. Then check by finding the standard deviation by hand .
What is sampling error? Could value of sampling error be zero? If it were zero, what would this mean?
What can we conclude from these figures at a level of significance of .01?
Stating assumptions on which your arguments and conclusions are based, sum up the statistical evidence regarding effectiveness of this diet.
Find the probability that 4 of the 5 committee members belong to a union.Find the probability using hypergeometric distribution.
Explain the ANOVA output table values:
Do these data suggest a statistically significance difference between the proportions of drug-resistant cases in the two states? Use a 0.02 level of significance and computed value of 2.37.
A case-control study of relationship between liver cirrhosis among both non alcoholics and alcoholics. Describe whether smoking is confounder.
Find the lowest possible score a candidate can score and still qualify. Assume the scores are normally distributed.
Both days have sample standard deviations of 3.4. Is the average mean of size different from day 1 to day 2?
A 95% confidence interval for µ is found to be 652 ± 21.56 = ($630.44, $673.56). Determine which of the following statements is true.
Health and Nutrition Examination Survey, suppose that weights of men now are normally distributed with mean of m =172 pounds and standard deviation of s = 29 pounds.
Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!
whatsapp: +1-415-670-9521
Phone: +1-415-670-9521
Email: [email protected]
All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd