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Question: A box of mass 4.75 kg is hanging from the end of a vertical rope of negligible mass. A force F(t) directed upward is applied to the end of the rope. The box's position y(t)above its initial position is given by y(t) = (2.65 m/s)t + (0.592 m/s3)t3.
Part A: What is the magnitude of the force when t = 3.75 s?
Please show work on how to solve!
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