Compute delta g don''t change with temperature

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Consider this reaction, NO2(g) + N2O (g) -->3 NO (g).

(a) Predict how Delta G^o for this reaction varies with increasing temperature.

Substance Delta H^o Delta G^o Delta S^o

NO2(g) 33.84 51.84 240.45

N20(g) 81.6 103.59 240.45

NO(g) 90.37 86.71 210.62

(b) Calculate Delta G^o at 800 K, assuming that Delta H^o and Delta S^o do not change with temperature.

(c) Is the reaction spontaneous at 800K?

(d) Above what temperature will the reaction become spontaneous?

(d) Calculate Delta G^o at 1000 K. Is the reaction spontaneous at this temperature?

Reference no: EM13168941

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