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Perform a two tailed hypothesis test on both the legal services satisfaction and the sentence satisfaction variable's data using a 0.5 significance level by creating a null and a alternative statement.
Assume that the mean useful life of a particular lightbulb is 2,000 hours and is normally distributed with a standard deviation of 300 hours. Determine the percentage of lightbulbs that will last 2,300 hours or longer.
Assume that each of the following studies cannot be analyzed using a parametric procedure. For each of the following studies (below), indicate the appropriate nonparametric procedure, and explain why you chose it.
Use multiplication of Taylor series to find the quartic Taylor polynomial about 0 for the function h(x)=(cosx)ln(1+x) evaluating the cefficients
A number of minor automobile accidents occur at various high-risk intersections. A study was done. Eight intersections were chosen at random. The number of minor accidents during a 6-month period before and after the modifications were:
A sample of n=10 in each treatment. For this study, the three samples have SS1=10, SS2=20, and SS3=15. What value would be obtained for MSwithin?
Analyze the above alternatives with utility function U(x) = 0.0085x - 6.725(ln(x)), where x is total/net wealth: If Nancy has $5,600, which alternative he should choose among A, B or C?
An auto manufacturer advertises that "90% of the cars we've ever made are still on the road." Assuming this is literally true, how can it be explained?
Using α = 0.05, does this sample provide enough evidence to conclude that the average utility bill in Delaware was lower in the winter of 2011-2012 than it was in the winter of 2010-2011?
You want to show an increase in buying and selling of single-family homes this year when compared with last year's rate.
What is the explained return on an equally weighted portfolio of these three stocks? What is the variance of a portfolio invested 20 percent each in A and B and 40 percent in C?
One more box is tested, and if that passes, all bulbs made that day will pass. Find probability that first box fails and second box passes.
Take any number, square it, and add 6, multiply by the original number. Now add 5 to that. Now divide this by the original number plus 1. Now subtract your original number and you should get 5.
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