Calculate the % yield if you collect 0.008 moles of product

Reference no: EM13687236

Problem- Starting with 1.600 mL of an alcohol (MW 88, d = 0.8114 g/mL) and 3 mL of glacial acetic acid (MW 60, d=1.06 g/mL), calculate the % yield if you collect 0.008 moles of product. (0 digits after decimal point)

Compute the given problem to find accurate answer

Reference no: EM13687236

Questions Cloud

What is the major organic product : Problem- Part 1) What is the major organic product when (R)-3-methyl-1, 2-epoxybutane reacts with butylmagnesium bromide?

Determine the percent error in the students'' values : Problem- In Fall, 2011, General Chemistry I students found that the average molar heat of neutralization from hydrochloric acid and sodium hydroxide was -70.9 kJ/mol. the accepted value for this reaction is -57.3 kJ/mol. Determine the percent erro..

Explain what is the equilibrium concentration of the ethene : Explain what is the equilibrium concentration of the ethene (C2H4) in the vessel? Kc = 6.6 x10 ^8 at this temperature.

Calculate the % yield if you collect 0.008 moles of product : Problem- Starting with 1.600 mL of an alcohol (MW 88, d = 0.8114 g/mL) and 3 mL of glacial acetic acid (MW 60, d=1.06 g/mL), calculate the % yield if you collect 0.008 moles of product. (0 digits after decimal point)

Determine the wavelength (in nm) : Problem- An FM radio station has a frequency of 88.9 MHz (1MHz = 10*6 Hz). Determine the wavelength (in nm).

Calculate the activation energy : Problem- For a given first-order reaction, k is 2.6 x 10^-10 s-1 at 300 degrees C and 6.7 x 10^-4 s-1 at 500 degrees C. Calculate the activation energy.

Calculate the grams of 36% aa solution she needs : Calculate the grams of 36% AA solution she needs to makes and the grams of water she needs to add to make the 1.00kg of 15% solution.

Potassium bromide rather than potassium bromate : Problem- Describe and explain the possible effect on your results of the following experimental errors or variations. 1) The lab assistant set out a bottle of potassium bromide rather than potassium bromate.

User Account

All Pages