Calculate the ph of the solution

Reference no: EM13689959

Problem- There is a solution that is 3.8 x 10^-2 M in HCN (Ka = 4.9 x 10^-10) and 1 x 10^-2 M NaCN [H3O+][CN?],[HCN],[OH?],[Na+] =

1.86Ã-10?9,1.00Ã-10?2,3.80Ã-10?2,5.37Ã-10?6,1.00Ã-10?2

1) Calculate the pH of the solution

2) Calculate the dissociation of HCN in a solution.

Explain the each and every step in detail for help

Reference no: EM13689959

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