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The bellows, diaphragm, and Bourdon tube pressure sensors all exhibit second order time response. This means that a sudden change in pressure will cause an oscillation in the displacement and, therefore in the sensor output. Because they are like springs, they have an effective spring constant and mass, so the frequency can be estimated by f=(1/2*pi)(squk/m). Consider a bellows with an effective spring constant of 3500 N/m and a mass of 50 g. The effective area against which the pressure acts is 0.5in2. Calculate:
a. The bellows deflection for a pressure of 20 psi andb. The natural frequency of oscillation.
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