Reference no: EM13339313
A uniform beam of mass m= 100 kg and length L is inclined at angle theta equals 75 degrees to the horizontal. A horizontal cable runs from a wall to the beam and attaches at point A located a distance 4/5L from the pivot at the base of the beam. The load mass is M = 500 kg and the entire system is in static equilibrium.
A) calculate the magnitude of the force the load exerts on the beam.
B) assuming the axis of rotation is perpendicular to the page at the pivot, find an expression for the magnitude of the torque reduced by the load on the beam.
C) assuming the axis of rotation is perpindicular to the page at the pivot, find an expression for the magnitude of the torque on the beam produced by the beams own weight.
D) same a C but this team produced by the tension in the horizontal cable.
E) find the magnitude of the tension in the horizontal cable.
F) find the x component of the reaction force the pivot exerts on the beam.
G) find the y component of the reaction force the pivot exerts on the beam.
H) while the tilt angle theta equals 75 degrees is held constant, the load is slowly lifted vertically by a winch until the length of the vertical cable is negligible, and the load mass effectively sits at the upper end of the beam. At that instant, the horizontal cable snaps. Given that the length of the beam is L = 10 meters, calculate the magnitude of the systems angular acceleration at the instant the horizontal cable fails( hint: start by finding the moment of inertia of the entire system consisting of the beam + load mass).
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