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Problem- Enough of a monoprotic acid is dissolved in water to produce a 0.0123 M. The PH of the resulting solution is 2.58. Calculate the Ka for the acid.
I just need a general explanation of it please- Thanks
The free energy change Delta GT at 2400 K is equal to 1.22*10^5 J/mol. Calculate the equilibrium constant at 2400 K.
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