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A 30 ft tape weighing 3 lb and with a cross sectional area of 0.01 in2 was standardized and found to be 30.02 ft at 680F, with 20 lb tension and fully supported . This tape was used to measure a total distance of about 80 ft. The first 60 ft has a uniform 30% slope but the other 20 m was horizontal. The temperature was constant at 850 F, the tape was fully supported throughout and a tension of 30 lb was applied to each tape length. The observed distances were 30.0 ft, 30.0 ft., and 20.0 ft. Calculate the horizontal distance between the points.
Assume E = 3 x 107 lb/in2
and K = 6.45 x 10-6 per unit length per 0F.
Hint: This problem is very similar to the second problem we solved in class (see the detailed PowerPoint presentation I posted). Just to assist you to solving this I am drawing a sketch of how the profile looks.
Do not apply the length correction here.
Going through the presentation "Tape Corrections Explained" will definitely help you in this.
Last but not the least: Please do not hesitate to ask me questions
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