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Problem- The concentrations of NaCl and KI are at 0.150M and 0.100M respectively, in the following electrochemical cell
Cu(s) | CuI(s) | I-(aq) || Cl-(aq) | AgCl(s) | Ag(s)
a) Using the following half-reactions, calculate cell voltage
CuI(s) + e- <--> Cu(s) + I- Eo = -0.185V
AgCl(s) + e- <--> Ag(s) + Cl- Eo = 0.222V
b) Now calculate the cell voltage using the following half-reactions. The Ksp for AgCl and CuI are 1.8E-10 and 1.0E-12 respectively.
Cu+ + e- <--> Cu(s) Eo = 0.518V
Ag+ + e- <--> Ag(s) Eo = 0.7993V
Show all steps to describe the solution of above problem
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