Calculate the capacitance the charge on capacitor plates

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Reference no: EM13558803

Figure 25-18 shows a parallel-plate capacitor of plate areaA and plate separation d. A potential differenceV₀ is applied between the plates. While thebattery remains connected, a dielectric slab of thicknessb and dielectric constant κ is placed between the plates as shown. Assume A = 190 cm², d= 1.30 cm, V₀ = 88.5 V, b = 0.950 cm,and κ = 4.89. Calculate (a) the capacitance,(b) the charge (in C) on the capacitor plates,(c) the electric field in the gap, and (d) the electric field in the slab, after the slab is in place.

Reference no: EM13558803

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