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Question- The reversible work involved in twisting a short DNA molecule depends quadratically on /\phi/ L, the angle of twist per unit length, where the twist angle is expressed in units of radians. The expression for the reversible work is wtwist= CL/2 (\phi /L)2. A DNA oligomer, 20 base pairs in length, undergoes a twisting deformation of 36 degrees in order to bind to a protein. Calculate the reversible work involved in this twisting deformation.
Assume C = 2.5*10^-28 J*m, and that each base pair is 3.4*10^-10 m in length.
I am need of complete solution for this problem please help- me out to get right solution
In a reaction of copper with nitric acid, if 4.00 g of copper is used, how much copper nitrate will be produced
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