Calculate {pb2+} when ecell is 1.07 v

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Question- A voltaic cell consists of an Mn/Mn2+ half-cell and a Pb/Pb2+ half-cell. Calculate {Pb2+} when Ecell is 1.07 V and {Mn2+} = 0.681 M. Use reduction potential values of Mn2+ = -1.18 V and for Pb2+ = -0.13 V.

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Reference no: EM13697821

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