Calculate a 95 confidence interval for the corresponding

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A survey of 175 gun owners was taken, and 44.3% of them said they "have a gun for protection for self and/or family." Is there evidence to conclude that the percentage of gun owners have guns for protection of self and/or family is significantly different from 50%?

(a) State the hypotheses.

(b) Using a 5% significance level, determine the rejection and non-rejection regions.

(c) Calculate the test statistic, and interpret the result.

(d) Calculate the p-value, and interpret the result.

(e) Calculate a 95% confidence interval for the corresponding population proportion. How does this result related to the conclusions in parts (c) and (d)?

Details are welcome, as much as possible

Reference no: EM13633196

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