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Based on information from the Rocky Mountain News, a random sample of 12 winter days in Denver gave a mean pollution index of 43 with a standard deviation of 21. For Englewood (a suburb of Denver), a random sample of 14 winter days gave a mean pollution index of 36 with a standard deviation of 15. Find a 95% confidence interval for 1-2.
A. (29.657,56.343)
B. (27.339,44.661)
C. (2.318,11.682)
D. (-8.182,22.182)
If a sample of 20 dish owners is randomly selected the what would be the probability that more than 11 dish owners in the sample subscribe to at least one premium movie channel?
This fits the form of a binomial experiment situation. Develop a 95% confidence statement. Show all of the steps. How do you do this?
Is it reasonable typical worker does not miss any days during a pay period?
The following table summarizes data between money spent on gambling and winnings for Robert.
If a random sample of 500 students sit for an exam find the probability that 18% to 23% of the students in the sample will pass it the first time.
a fair 4 sided die has the numbers 123 and 4 on its faces. the die is rolled 20 times. the random variable x represents
market researcher gartner dataquest reports that dell computer controls 27 of the pc market in the united states.
According to the National Football League, the average salary for players for the 2010 season was about $1.9 million while the median salary is around $770,000. Why are both numbers reported? What might the difference between the two statistics me..
While 290 out of 400 in Batavia preferred the same flavor. To test the hypothesis that there was no difference in preferences in the two towns, what is the alternate hypothesis?
which of the following is not an advantage of nonparametric methods over parametric methods?a they can be used when the
a manufacturer of window frames knows from experince that 1 percent of the production will have some type of minor
The question is, is it just sampling error that accounts for the difference, or is the local store different than the national numbers? This is a typical chi-square problem.
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