Average acceleration aavg in the time interval

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Fromt= 0 tot= 4.39 min, a man stands still, and fromt= 4.39 mintot= 8.78 min, he walks briskly in a straight line at a constant speed of2.01 m/s. What are(a)his average velocityvavgand(b)his average accelerationaavgin the time interval 1.00 min to5.39 min?What are(c)vavgand(d)aavgin the time interval2.00 minto6.39 min?

A startled armadillo leaps upward, rising 0.546 m in the first 0.209 s.(a)What is its initial speed as it leaves the ground?(b)What is its speed at the height of 0.546 m?(c)How much higher does it go?

A certain elevator cab has a total run of 205 m and a maximum speed is 307 m/min, and it accelerates from rest and then back to rest at 1.12 m/s2.(a)How far does the cab move while accelerating to full speed from rest?(b)How long does it take to make the nonstop 205 m run, starting and ending at rest?Catapulting mushrooms. Certain mushrooms launch their spores by a catapult mechanism. As water condenses from the air onto a spore that is attached to the mushroom, a drop grows on one side of the spore and a film grows on the other side. The spore is bent over by the drop's weight, but when the film reaches the drop, the drop's water suddenly spreads into the film and the spore springs upward so rapidly that it is slung off into the air. Typically, the spore reaches a speed of1.70 m/sin a5.00mlaunch; its speed is then reduced to zero in1.00 mmby the air. Using that data and assuming constant accelerations, find the acceleration in terms ofgduring(a)the launch and(b)the speed reduction

Reference no: EM13828782

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Average acceleration aavg in the time interval : Fromt= 0 tot= 4.39 min, a man stands still, and fromt= 4.39 mintot= 8.78 min, he walks briskly in a straight line at a constant speed of2.01 m/s. What are(a)his average velocityvavgand(b)his average accelerationaavgin the time interval 1.00 min to5.3..
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