Assume the skin temperature of a naked person

Reference no: EM13660059

Assume the skin temperature of a naked person is 34° C when the person is standing inside a room whose temperature is18° C. The skin area of the individual is 1.4 m2.

a) Assuming the emissivity is 0.80, find the net loss of radiant power from the body.

b) Decide the number of food Calories of energy (1 food Calorie= 4186 J) that is lost in one hour due to the net loss rate obtained in part (a). Metabolic conversion of food into energy replaces this loss.

Reference no: EM13660059

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