Solution-Angular acceleration-number of revolution

Angular acceleration-number of revolution

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Reference no: EM13833587

A perfectly circular hoop of mass m = 6 kg and radius r = 0.4m rotate on a horizontal plane on a vertical axis passing through its center. At t = 0 the hoop rotates at a rate of 400 rpm but 12 s later it stops because of frictional torque. Assuming constant acceleration calculate.

a) The angular acceleration

b) The number of revolution the hoop did during this time

c) Total linear acceleration (only magnitude) of a bug seating at the edge of the hoop at t = 10s.

d) Frictional torque

Reference no: EM13833587

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Angular acceleration-number of revolution : A perfectly circular hoop of mass m = 6 kg and radius r = 0.4m rotate on a horizontal plane on a vertical axis passing through its center. At t = 0 the hoop rotates at a rate of 400 rpm but 12 s later it stops because of frictional torque. Assumin..

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Angular acceleration-number of revolution

Reference no: EM13833587

Reference no: EM13833587

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