Reference no: EM13999570
1. At 35oC, Kc=0.0959 for the reaction below.
H2 + Cl2 --> 2 HCl
In an experiment carried out at 35oC, the initial concentrations were [H2]=[Cl2]=[HCl]=1.50mol/L. What is the equilibrium concentration of HCl?
2. Some CH4(g), intially at 1.000 atm, is placed in an empty reaction vessel. At equilibrium, the total pressure is 1.981 atm. Assuming the partial pressures are in atmospheres, what is Kp for the reaction below?
2 CH4(g) → C2H2(g) + 3 H2(g)
3. Consider the following reaction.
BaSO4(s) → Ba2+(aq) + SO42-(aq), Kc = [Ba2+] [SO42- ] = 1.08x10-10
A solution is prepared by adding some solid BaSO4 to water and allowing the solid to come to equilibrium with the solution. What are the concentrations of Ba2+ and SO42- in the solution?
4. Suppose that A and B react to form C according to the equation below.
A + 2B → C
What are the equilibrium concentrations of A, B and C if 1.5 mol A and 1.5 mol B are added to a 1.0 L flask? Assume that the equilibrium constant for this reaction is Kc = 4.9x1011.
5. A solution is prepared by adding some solid SrF2 to water and allowing the solid to come to equilibrium with the solution. The equilibrium constant for the reaction below is Kc = 7.9x10-10.
SrF2(s) → Sr2+(aq) + 2 F -(aq)
What is the equilibrium concentration of Sr2+ in the solution? Assume that some of the solid remains undissolved.
6. At 2000 K, Kc = 0.154 for the reaction below.
2 CH4(g) → C2H2(g) + 3 H2(g)
If a 1.75-L equilibrium mixture at 2000 K contains 0.15 mol each of CH4(g) and H2(g), answer the following questions.
(a) What is the mole fraction of CH4 present? (Note: The mole fraction of CH4 is equal to the number of moles of CH4 divided by the total number of moles.)
Enter your answer with 2 significant digits.
Enter scientific notation as 1.23E4.
Enter only numbers in your answer. (Do not include units.)
The mole fraction of CH4 is ____________
(b) If the equilibrium mixture at 2000 K is transferred from a 1.75-L flask to 1.50-L flask, will the number of moles of CH4(g) increase, decrease, or remain unchanged?
I have attempted the questions however I keep getting it incorrect.
My answers
1. 2.75M
2. Kp=16210
3. 1.039x10^-5
4. [A]=1.056 [B]=0.61237 [C]=0.443813
5. 0.053M
6. I am not really sure how to solve it
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